Cos^2x+5cosx+4=0

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Solution for Cos^2x+5cosx+4=0 equation: 


Simplifying
Cos2x + 5cosx + 4 = 0

Reorder the terms:
4 + 5cosx + os2xC = 0

Solving
4 + 5cosx + os2xC = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 5cosx + -4 + os2xC = 0 + -4

Reorder the terms:
4 + -4 + 5cosx + os2xC = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 5cosx + os2xC = 0 + -4
5cosx + os2xC = 0 + -4

Combine like terms: 0 + -4 = -4
5cosx + os2xC = -4

Add '-1os2xC' to each side of the equation.
5cosx + os2xC + -1os2xC = -4 + -1os2xC

Combine like terms: os2xC + -1os2xC = 0
5cosx + 0 = -4 + -1os2xC
5cosx = -4 + -1os2xC

Divide each side by '5osx'.
c = -0.8o-1s-1x-1 + -0.2sC

Simplifying
c = -0.8o-1s-1x-1 + -0.2sC

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